Eight drops of mercury, each of same radius and same charge combine to form a bigger drop. The ratio of capacitance of the bigger drop to that of each smaller drop is
Text Solution
Verified by ExpertsThe correct answer is:
C
Number of drops, 
Let, r is radius of smaller drop and R is the radius of Bigger drop.
Volume of smaller drops & bigger drop remains same

Capacitance of spherical conductor,
Ratio of capacitance of bigger drop to smaller drop is given as


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